Quantitative Techniques — 2023

KNEC Diploma in Supply Chain Management, Module II. Original theory examination questions with explained model answers for revision.


July 2023

Paper codes: 2903/204
Time: 3 hours
Instructions: Answer any FIVE questions. All questions carry equal marks. Answer the questions in English.

Question 1(a) — 10 marks

Explain five requirements of a linear programming problem.

Model answer

  1. An explicit objective must be specified, such as maximizing profit or minimizing cost, expressed as a linear function of the decision variables.
  2. Clearly defined decision variables represent the quantities the business can choose.
  3. Resource limits or business requirements must be expressible as linear equality or inequality constraints.
  4. Relationships must be proportional and additive: coefficients remain constant, with no products or powers of decision variables; continuous divisibility is assumed unless integer restrictions are added.
  5. Coefficients are treated as known with certainty and feasible sign restrictions, normally non-negativity, must be specified so the solution has business meaning.

Question 1(b) — 10 marks

The following information relates to ten machines at Okwot Enterprises.

Age of machine (years) Annual maintenance cost Ksh 000
12 60
8 52
10 55
4 30
7 40
2 20
11 58
10 54
10 50
15 70

(i) Calculate the Pearson’s correlation co-efficient.

(ii) Interpret the results in (i) above.

Model answer

Let x be age and y be annual maintenance cost in Ksh thousands. n = 10.

x y x² y² xy
12 60 144 3,600 720
8 52 64 2,704 416
10 55 100 3,025 550
4 30 16 900 120
7 40 49 1,600 280
2 20 4 400 40
11 58 121 3,364 638
10 54 100 2,916 540
10 50 100 2,500 500
15 70 225 4,900 1,050
89 489 923 25,909 4,854

r = [nΣxy − ΣxΣy]/√{[nΣx² − (Σx)²][nΣy² − (Σy)²]} = 5,019.0000/5,112.6726 = 0.981678.

There is a strong positive linear association: older machines tend to have higher annual maintenance costs. Correlation alone does not establish that age is the only cause of the cost difference.

Question 2(a) — 10 marks

Explain five roles of quantitative techniques in business decision making.

Model answer

  1. Forecasting demand and sales from data helps determine future production, purchasing and staffing requirements.
  2. Optimisation allocates scarce labour, materials and machine time to the activities that best meet a stated objective.
  3. Inventory models balance ordering, holding and shortage costs to guide replenishment decisions.
  4. Project scheduling identifies activity dependencies, completion times and critical tasks so managers can control delivery.
  5. Probability and statistical analysis measure uncertainty, compare alternatives and test claims, supporting more consistent risk-informed decisions.

Question 2(b) — 10 marks

The total cost of one pencil and one eraser in a shop is Ksh 70. The total cost of three similar pencils exceeds the total cost of two similar erasers by Ksh 110.

(i) Formulate simultaneous equations from the information above.

(ii) Using matrix method, solve the simultaneous equations in (i) above to determine the cost of each item.

(iii) Determine the total cost of five pencils and eight erasers.

Model answer

Let x = pencil price and y = eraser price. Then x + y = 70 and 3x − 2y = 110. In matrix form AX = b, with A =

1 1
3 -2

and b =

70
110

det A = −2 − 3 = −5; A⁻¹ = (−1/5)

-2 -1
-3 1

X = A⁻¹b = (−1/5)[−140−110, −210+110]ᵀ = [50,20]ᵀ.

Step / item Working Result
Pencil price x 50
Eraser price y 20
Five pencils and eight erasers 5×50 + 8×20 410

Check: 50 + 20 = 70; 3×50 − 2×20 = 110.

Question 3(a) — 10 marks

Explain the importance of Time Series analysis in decision making.

Model answer

  1. It reveals the long-term trend in sales, costs or demand, helping managers plan growth and capacity.
  2. It identifies seasonal patterns so purchasing, staffing and cash availability can be adjusted before predictable peaks and troughs.
  3. It supports forecasts based on observed historical movement, providing inputs for budgets and operating plans.
  4. It separates regular patterns from unusual movements, helping managers investigate shocks or changes in performance.
  5. It provides a benchmark for comparing actual results with expected patterns and assessing whether corrective action is needed.

Question 3(b) — 10 marks

The following is the Marginal Revenue (MR) function of a firm.

MR = 20 − 0.5q

Where q is the level of output sold by the firm. Determine the:

(i) total revenue function;

(ii) level of output that will maximize the total revenue;

(iii) maximum total revenue;

(iv) price at maximum total revenue.

Model answer

Step Working
Integrate marginal revenue TR = ∫(20 − 0.5q)dq = 20q − 0.25q² + C
Boundary condition TR(0)=0 ⇒ C=0, so TR=20q−0.25q²
Maximising output dTR/dq = MR = 20 − 0.5q = 0 ⇒ q=40 units
Second derivative d²TR/dq² = −0.5 < 0, confirming a maximum
Maximum total revenue TR(40)=800−400=400 monetary units
Price at that output P=TR/q=400/40=10 monetary units per unit

Question 4(a) — 8 marks

Explain four problems that may be encountered when constructing index numbers.

Model answer

  1. Selecting a representative base year is difficult when available years contain unusual inflation, shortages or other shocks.
  2. Choosing representative commodities and obtaining comparable prices can be difficult because consumption differs among households and locations.
  3. Selecting suitable weights is challenging, and old weights become misleading as expenditure patterns change.
  4. Quality changes, new products, disappearing products and different units of sale reduce comparability over time and may require adjustments.

Question 4(b) — 12 marks

Figure 1 is a network diagram of a project to be undertaken by a firm. The time duration is given in days.

2023 Q4(b): redrawn source network — activity (days)
2023 Q4(b): redrawn source network — activity (days)

(i) Prepare a table showing the activity, preceding activity and the duration.

(ii) Determine the: (I) critical path; (II) project duration.

Model answer

The event numbers are added to the redrawing for reference; activity labels and durations retain the supplied network. An activity leaving a merge event waits for all activities entering that event.

Activity Preceding activities Duration days ES EF LS LF Float
A — 5 0 5 0 5 0
B A 10 5 15 5 15 0
C A 5 5 10 20 25 15
D B 10 15 25 15 25 0
E A 10 5 15 29 39 24
F B 15 15 30 28 43 13
G C,D 6 25 31 37 43 12
H C,D 8 25 33 43 51 18
I F,G 8 31 39 43 51 12
J C,D 14 25 39 25 39 0
K E,J 12 39 51 39 51 0
L H,I,K 10 51 61 51 61 0

Forward pass: take the maximum finish of all predecessors. Backward pass: take the minimum start of successors. The zero-float path is A → B → D → J → K → L, taking 5 + 10 + 10 + 14 + 12 + 10 = 61 days.

Question 5(a) — 8 marks

Explain four poor stock management practices that may make a firm to accumulate high levels of stock.

Model answer

  1. Ordering quantities beyond realistic demand or buying merely to obtain discounts creates excess inventory and ties up cash.
  2. Poor or outdated demand forecasting causes purchases to continue after demand has fallen or product preferences have changed.
  3. Inaccurate stock records and weak coordination allow duplicate orders for stock already held or on order.
  4. Failure to review slow-moving and obsolete stock, enforce reorder limits or dispose of unwanted items allows old stock to accumulate.

Question 5(b) — 12 marks

The following are prices and quantities of four commodities in a market for the years 2015 and 2018.

Commodity 2015 price p₀ Ksh 2015 quantity q₀ 2018 price p₁ Ksh 2018 quantity q₁
A 40 100 50 75
B 60 500 80 600
C 80 350 120 400
D 100 120 80 100

Determine the: (i) Laspeyre’s price index; (ii) Paasche’s price index; (iii) Fisher’s ideal price index.

Model answer

Commodity p₀q₀ p₁q₀ p₀q₁ p₁q₁
A 4,000 5,000 3,000 3,750
B 30,000 40,000 36,000 48,000
C 28,000 42,000 32,000 48,000
D 12,000 9,600 10,000 8,000
Total 74,000 96,600 81,000 107,750
Step / item Working Result
Laspeyres price index 96,600/74,000 × 100 130.54
Paasche price index 107,750/81,000 × 100 133.02
Fisher ideal price index √(130.540541 × 133.024691) 131.78

Question 6(a) — 12 marks

Distinguish between each of the following terms as used in the test of hypothesis: (i) Type I error and Type II error; (ii) critical region and acceptance region; (iii) Z-test and T-test.

Model answer

Pair First term Second term
Type I / Type II error Type I: reject a true H₀. Its probability is α, the significance level. Type II: fail to reject a false H₀. Its probability is β; power is 1−β.
Critical / acceptance region Critical region contains test-statistic values leading to rejection of H₀ at the chosen α. The non-rejection region contains values for which evidence is insufficient to reject H₀; it does not prove H₀.
Z-test / t-test A Z-test uses the standard normal distribution, e.g. a mean test with known population standard deviation or a suitable large-sample approximation. A one-sample t-test for a mean uses sample standard deviation when population σ is unknown, with n−1 degrees of freedom and appropriate normality/independence assumptions. The t distribution has heavier tails, especially for small samples.

Question 6(b) — 8 marks

John intends to invest Ksh 3,000,000 for a period of five years in either option A or option B.

Option A: deposit the amount in an account paying interest at the rate of 10% per annum compounded semi-annually.

Option B: invest the amount in a fund paying interest at the rate of 8% per annum compounded quarterly.

(i) Determine the total amount that will be available to John under each option at the end of five years.

(ii) Calculate the interest that will be earned under each option.

(iii) Based on the results in (ii) above, advise John on the option to invest in.

Model answer

Compound amount F = P(1 + r/m)ᵐᵗ. Interest = F − P.

Option Periodic rate Periods Future amount Ksh Interest Ksh
A 10%/2 = 5% 10 4,886,683.88 1,886,683.88
B 8%/4 = 2% 20 4,457,842.19 1,457,842.19

On the rates given and assuming equal risk, charges and access conditions, choose A: it earns Ksh 428,841.69 more over five years. This is the comparison requested by the examination data.

Question 7(a) — 10 marks

In the “Jua Kali” sector, the percentage of male entrepreneurs is 70%. A random sample of ten entrepreneurs was selected from the sector. Determine the probability of selecting:

(i) one male entrepreneur;

(ii) no male entrepreneur;

(iii) at least one male entrepreneur;

(iv) at most eight male entrepreneurs.

Model answer

Let X ~ Binomial(10,0.7), assuming independent selections with constant probability. P(X=k)=C(10,k)0.7ᵏ0.3¹⁰⁻ᵏ.

Part Working Probability
(i) 10×0.7×0.3⁹ 0.000137781
(ii) 0.3¹⁰ 0.000005905
(iii) 1−0.3¹⁰ 0.999994095
(iv) 1−[10×0.7⁹×0.3 + 0.7¹⁰] 0.850691654

Question 7(b) — 10 marks

The following are the sales of a company for ten consecutive years.

Year Sales Ksh million
2000 40
2001 38
2002 42
2003 50
2004 48
2005 52
2006 65
2007 65
2008 70
2009 72

(i) Using three year moving averages, determine the trend values.

(ii) Comment on the trend in the sales.

Model answer

Average each consecutive group of three years and place the result against the middle year.

Centred year Window Three-year total Moving average Ksh million
2001 2000–2002 120 40
2002 2001–2003 130 43.33
2003 2002–2004 140 46.67
2004 2003–2005 150 50
2005 2004–2006 165 55
2006 2005–2007 182 60.67
2007 2006–2008 200 66.67
2008 2007–2009 207 69

The smoothed sales trend rises from Ksh 40.00 million in 2001 to Ksh 69.00 million in 2008, with faster growth in the later years. There is no centred three-year value for 2000 or 2009 because an adjoining year is missing at each end.